3. A screening test for a disease has a sensitivity of 90% and a specificity of 80%. In a population of 1,000 individuals, 100 have the disease. How many of the 900 individuals who do not have the disease will test positive on the screening test?
The number of individuals who do not have the disease in the population is 1,000 – 100 = 900.
Since the sensitivity of the test is 90%, 90 out of 100 individuals with the disease will test positive.
Therefore, the number of individuals who test positive among those who have the disease is 90.
Since the specificity of the test is 80%, 20% of the 900 individuals who do not have the disease will test positive.
Therefore, the number of individuals who test positive among those who do not have the disease is 900 x 0.20 = 180.
Thus, the answer is 180.
The number of individuals who do not have the disease in the population is 1,000 – 100 = 900.
Since the sensitivity of the test is 90%, 90 out of 100 individuals with the disease will test positive.
Therefore, the number of individuals who test positive among those who have the disease is 90.
Since the specificity of the test is 80%, 20% of the 900 individuals who do not have the disease will test positive.
Therefore, the number of individuals who test positive among those who do not have the disease is 900 x 0.20 = 180.
Thus, the answer is 180.